Integrand size = 20, antiderivative size = 174 \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\frac {b d p}{e \left (b d^2+a e^2\right ) (d+e x)}+\frac {2 \sqrt {a} b^{3/2} d p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\left (b d^2+a e^2\right )^2}-\frac {b \left (b d^2-a e^2\right ) p \log (d+e x)}{e \left (b d^2+a e^2\right )^2}+\frac {b \left (b d^2-a e^2\right ) p \log \left (a+b x^2\right )}{2 e \left (b d^2+a e^2\right )^2}-\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2} \]
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Time = 0.10 (sec) , antiderivative size = 174, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {2513, 815, 649, 211, 266} \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\frac {2 \sqrt {a} b^{3/2} d p \arctan \left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\left (a e^2+b d^2\right )^2}-\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2}+\frac {b p \left (b d^2-a e^2\right ) \log \left (a+b x^2\right )}{2 e \left (a e^2+b d^2\right )^2}+\frac {b d p}{e (d+e x) \left (a e^2+b d^2\right )}-\frac {b p \left (b d^2-a e^2\right ) \log (d+e x)}{e \left (a e^2+b d^2\right )^2} \]
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Rule 211
Rule 266
Rule 649
Rule 815
Rule 2513
Rubi steps \begin{align*} \text {integral}& = -\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2}+\frac {(b p) \int \frac {x}{(d+e x)^2 \left (a+b x^2\right )} \, dx}{e} \\ & = -\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2}+\frac {(b p) \int \left (-\frac {d e}{\left (b d^2+a e^2\right ) (d+e x)^2}+\frac {e \left (-b d^2+a e^2\right )}{\left (b d^2+a e^2\right )^2 (d+e x)}+\frac {b \left (2 a d e+\left (b d^2-a e^2\right ) x\right )}{\left (b d^2+a e^2\right )^2 \left (a+b x^2\right )}\right ) \, dx}{e} \\ & = \frac {b d p}{e \left (b d^2+a e^2\right ) (d+e x)}-\frac {b \left (b d^2-a e^2\right ) p \log (d+e x)}{e \left (b d^2+a e^2\right )^2}-\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2}+\frac {\left (b^2 p\right ) \int \frac {2 a d e+\left (b d^2-a e^2\right ) x}{a+b x^2} \, dx}{e \left (b d^2+a e^2\right )^2} \\ & = \frac {b d p}{e \left (b d^2+a e^2\right ) (d+e x)}-\frac {b \left (b d^2-a e^2\right ) p \log (d+e x)}{e \left (b d^2+a e^2\right )^2}-\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2}+\frac {\left (2 a b^2 d p\right ) \int \frac {1}{a+b x^2} \, dx}{\left (b d^2+a e^2\right )^2}+\frac {\left (b^2 \left (b d^2-a e^2\right ) p\right ) \int \frac {x}{a+b x^2} \, dx}{e \left (b d^2+a e^2\right )^2} \\ & = \frac {b d p}{e \left (b d^2+a e^2\right ) (d+e x)}+\frac {2 \sqrt {a} b^{3/2} d p \tan ^{-1}\left (\frac {\sqrt {b} x}{\sqrt {a}}\right )}{\left (b d^2+a e^2\right )^2}-\frac {b \left (b d^2-a e^2\right ) p \log (d+e x)}{e \left (b d^2+a e^2\right )^2}+\frac {b \left (b d^2-a e^2\right ) p \log \left (a+b x^2\right )}{2 e \left (b d^2+a e^2\right )^2}-\frac {\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2} \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 217, normalized size of antiderivative = 1.25 \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\frac {\frac {b p (d+e x) \left (\left (\sqrt {-a} b d^2+2 a \sqrt {b} d e+(-a)^{3/2} e^2\right ) (d+e x) \log \left (\sqrt {-a}-\sqrt {b} x\right )+\left (\sqrt {-a} b d^2-2 a \sqrt {b} d e+(-a)^{3/2} e^2\right ) (d+e x) \log \left (\sqrt {-a}+\sqrt {b} x\right )+2 \sqrt {-a} \left (b d^3+a d e^2-\left (b d^2-a e^2\right ) (d+e x) \log (d+e x)\right )\right )}{\sqrt {-a} \left (b d^2+a e^2\right )^2}-\log \left (c \left (a+b x^2\right )^p\right )}{2 e (d+e x)^2} \]
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Time = 2.02 (sec) , antiderivative size = 147, normalized size of antiderivative = 0.84
method | result | size |
parts | \(-\frac {\ln \left (c \left (b \,x^{2}+a \right )^{p}\right )}{2 e \left (e x +d \right )^{2}}+\frac {p b \left (\frac {\left (a \,e^{2}-b \,d^{2}\right ) \ln \left (e x +d \right )}{\left (a \,e^{2}+b \,d^{2}\right )^{2}}+\frac {d}{\left (a \,e^{2}+b \,d^{2}\right ) \left (e x +d \right )}+\frac {b \left (\frac {\left (-a \,e^{2}+b \,d^{2}\right ) \ln \left (b \,x^{2}+a \right )}{2 b}+\frac {2 a d e \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{\sqrt {a b}}\right )}{\left (a \,e^{2}+b \,d^{2}\right )^{2}}\right )}{e}\) | \(147\) |
risch | \(\text {Expression too large to display}\) | \(2684\) |
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Leaf count of result is larger than twice the leaf count of optimal. 362 vs. \(2 (162) = 324\).
Time = 0.36 (sec) , antiderivative size = 744, normalized size of antiderivative = 4.28 \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\left [\frac {2 \, {\left (b^{2} d^{3} e + a b d e^{3}\right )} p x + 2 \, {\left (b d e^{3} p x^{2} + 2 \, b d^{2} e^{2} p x + b d^{3} e p\right )} \sqrt {-a b} \log \left (\frac {b x^{2} + 2 \, \sqrt {-a b} x - a}{b x^{2} + a}\right ) + 2 \, {\left (b^{2} d^{4} + a b d^{2} e^{2}\right )} p + {\left ({\left (b^{2} d^{2} e^{2} - a b e^{4}\right )} p x^{2} + 2 \, {\left (b^{2} d^{3} e - a b d e^{3}\right )} p x - {\left (3 \, a b d^{2} e^{2} + a^{2} e^{4}\right )} p\right )} \log \left (b x^{2} + a\right ) - 2 \, {\left ({\left (b^{2} d^{2} e^{2} - a b e^{4}\right )} p x^{2} + 2 \, {\left (b^{2} d^{3} e - a b d e^{3}\right )} p x + {\left (b^{2} d^{4} - a b d^{2} e^{2}\right )} p\right )} \log \left (e x + d\right ) - {\left (b^{2} d^{4} + 2 \, a b d^{2} e^{2} + a^{2} e^{4}\right )} \log \left (c\right )}{2 \, {\left (b^{2} d^{6} e + 2 \, a b d^{4} e^{3} + a^{2} d^{2} e^{5} + {\left (b^{2} d^{4} e^{3} + 2 \, a b d^{2} e^{5} + a^{2} e^{7}\right )} x^{2} + 2 \, {\left (b^{2} d^{5} e^{2} + 2 \, a b d^{3} e^{4} + a^{2} d e^{6}\right )} x\right )}}, \frac {2 \, {\left (b^{2} d^{3} e + a b d e^{3}\right )} p x + 4 \, {\left (b d e^{3} p x^{2} + 2 \, b d^{2} e^{2} p x + b d^{3} e p\right )} \sqrt {a b} \arctan \left (\frac {\sqrt {a b} x}{a}\right ) + 2 \, {\left (b^{2} d^{4} + a b d^{2} e^{2}\right )} p + {\left ({\left (b^{2} d^{2} e^{2} - a b e^{4}\right )} p x^{2} + 2 \, {\left (b^{2} d^{3} e - a b d e^{3}\right )} p x - {\left (3 \, a b d^{2} e^{2} + a^{2} e^{4}\right )} p\right )} \log \left (b x^{2} + a\right ) - 2 \, {\left ({\left (b^{2} d^{2} e^{2} - a b e^{4}\right )} p x^{2} + 2 \, {\left (b^{2} d^{3} e - a b d e^{3}\right )} p x + {\left (b^{2} d^{4} - a b d^{2} e^{2}\right )} p\right )} \log \left (e x + d\right ) - {\left (b^{2} d^{4} + 2 \, a b d^{2} e^{2} + a^{2} e^{4}\right )} \log \left (c\right )}{2 \, {\left (b^{2} d^{6} e + 2 \, a b d^{4} e^{3} + a^{2} d^{2} e^{5} + {\left (b^{2} d^{4} e^{3} + 2 \, a b d^{2} e^{5} + a^{2} e^{7}\right )} x^{2} + 2 \, {\left (b^{2} d^{5} e^{2} + 2 \, a b d^{3} e^{4} + a^{2} d e^{6}\right )} x\right )}}\right ] \]
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Timed out. \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\text {Timed out} \]
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Time = 0.34 (sec) , antiderivative size = 206, normalized size of antiderivative = 1.18 \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\frac {{\left (\frac {4 \, a b d e \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{{\left (b^{2} d^{4} + 2 \, a b d^{2} e^{2} + a^{2} e^{4}\right )} \sqrt {a b}} + \frac {{\left (b d^{2} - a e^{2}\right )} \log \left (b x^{2} + a\right )}{b^{2} d^{4} + 2 \, a b d^{2} e^{2} + a^{2} e^{4}} - \frac {2 \, {\left (b d^{2} - a e^{2}\right )} \log \left (e x + d\right )}{b^{2} d^{4} + 2 \, a b d^{2} e^{2} + a^{2} e^{4}} + \frac {2 \, d}{b d^{3} + a d e^{2} + {\left (b d^{2} e + a e^{3}\right )} x}\right )} b p}{2 \, e} - \frac {\log \left ({\left (b x^{2} + a\right )}^{p} c\right )}{2 \, {\left (e x + d\right )}^{2} e} \]
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Time = 0.30 (sec) , antiderivative size = 278, normalized size of antiderivative = 1.60 \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\frac {2 \, a b^{2} d p \arctan \left (\frac {b x}{\sqrt {a b}}\right )}{{\left (b^{2} d^{4} + 2 \, a b d^{2} e^{2} + a^{2} e^{4}\right )} \sqrt {a b}} + \frac {{\left (b^{2} d^{2} p - a b e^{2} p\right )} \log \left (b x^{2} + a\right )}{2 \, {\left (b^{2} d^{4} e + 2 \, a b d^{2} e^{3} + a^{2} e^{5}\right )}} - \frac {p \log \left (b x^{2} + a\right )}{2 \, {\left (e^{3} x^{2} + 2 \, d e^{2} x + d^{2} e\right )}} - \frac {{\left (b^{2} d^{2} p - a b e^{2} p\right )} \log \left (e x + d\right )}{b^{2} d^{4} e + 2 \, a b d^{2} e^{3} + a^{2} e^{5}} + \frac {2 \, b d e p x + 2 \, b d^{2} p - b d^{2} \log \left (c\right ) - a e^{2} \log \left (c\right )}{2 \, {\left (b d^{2} e^{3} x^{2} + a e^{5} x^{2} + 2 \, b d^{3} e^{2} x + 2 \, a d e^{4} x + b d^{4} e + a d^{2} e^{3}\right )}} \]
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Time = 2.04 (sec) , antiderivative size = 272, normalized size of antiderivative = 1.56 \[ \int \frac {\log \left (c \left (a+b x^2\right )^p\right )}{(d+e x)^3} \, dx=\frac {\ln \left (b^2\,x+\sqrt {-a\,b^3}\right )\,\left (b^2\,d^2\,p-a\,b\,e^2\,p+2\,d\,e\,p\,\sqrt {-a\,b^3}\right )}{2\,\left (a^2\,e^5+2\,a\,b\,d^2\,e^3+b^2\,d^4\,e\right )}-\frac {\ln \left (d+e\,x\right )\,\left (b^2\,d^2\,p-a\,b\,e^2\,p\right )}{a^2\,e^5+2\,a\,b\,d^2\,e^3+b^2\,d^4\,e}-\frac {\ln \left (c\,{\left (b\,x^2+a\right )}^p\right )}{2\,e\,\left (d^2+2\,d\,e\,x+e^2\,x^2\right )}-\frac {\ln \left (b^2\,x-\sqrt {-a\,b^3}\right )\,\left (a\,b\,e^2\,p-b^2\,d^2\,p+2\,d\,e\,p\,\sqrt {-a\,b^3}\right )}{2\,\left (a^2\,e^5+2\,a\,b\,d^2\,e^3+b^2\,d^4\,e\right )}+\frac {b\,d\,p}{\left (x\,e^2+d\,e\right )\,\left (b\,d^2+a\,e^2\right )} \]
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